题目内容
若z1=a+3i,z2=3+4i,且为纯虚数,则实数a=________;
若z1=a+2i,z2=3-4i,且为纯虚数,则实数a的值为________.
设f(z)=1-,z1=2+3i,z2=5-i,则f()=
-4-4i
4+4i
4-4i
-4+4i
若Z1=a+2i,Z2=3-4i,且为纯虚数,则实数a的值为_________.
若z1=a+3i,z2=3+4i,且为纯虚数,则实数a=________.