Question

不等式＜x+1的解集是(    )

A.{x|x＞-3}                       B.{x|＜x＜2}

C.{x|x＜1}                        D.{x|-＜x＜1或x＞}

Answer 1

解析:当x＞1时,原不等式x²-1＞1,即x²＞,即x＞2或x＜-(舍).当x＜1时,原不等式1＞x²-1,即x²＜2,-＜x＜,∴-＜x＜1.

答案:D