题目内容
设已知
=(2cos
,sin
),
=(cos
,3sin
),其中α、β∈(0,π).
(1)若α+β=
,且
=2
,求α、β的值;
(2)若
•
=
,求tanαtanβ的值.
| a |
| α+β |
| 2 |
| α-β |
| 2 |
| b |
| α+β |
| 2 |
| α-β |
| 2 |
(1)若α+β=
| 2π |
| 3 |
| a |
| b |
(2)若
| a |
| b |
| 5 |
| 2 |
(1)∵α+β=
,∴
=(1,sin(α-
)),
=(
,3sin(α-
)),(2分)
由
=2
,得sin(α-
)=0,α∈(0,π),(4分)
∴α=
,β=
,(7分)
(2)∵
•
=2cos22cos(
)-3sin2
=1+cos(α+β)+3×
=
+cos(α+β)-
cos(α-β)(10分)
∴
+cos(α+β)-
cos(α-β)=
,即cos(α+β)=
cos(α-β),
整理得-5sinαsinβ=cosαcosβ,(12分)
∵α、β∈A,∴tanαtanβ=-
.(14分)
| 2π |
| 3 |
| a |
| π |
| 3 |
| b |
| 1 |
| 2 |
| π |
| 3 |
由
| a |
| b |
| π |
| 3 |
∴α=
| π |
| 3 |
| π |
| 3 |
(2)∵
| a |
| b |
| α+β |
| 2 |
| α-β |
| 2 |
| 1-cos(α-β) |
| 2 |
=
| 5 |
| 2 |
| 3 |
| 2 |
∴
| 5 |
| 2 |
| 3 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
整理得-5sinαsinβ=cosαcosβ,(12分)
∵α、β∈A,∴tanαtanβ=-
| 1 |
| 5 |
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