题目内容
(坐标系与参数方程选做题)在极坐标系中,过点(
,
)作圆ρ=
的切线,则切线的直角坐标方程是______.
| 2 |
| π |
| 4 |
| 2 |
∵点P(
,
),∴x=
cos
=1,y=
sin
=1,∴P(1,1).
∵圆ρ=
,化为普通方程:
=
,即x2+y2=2.
∵点P(1,1)满足圆的方程,∴点P在圆上.
∵KOP=
=1,
∴过点P的圆的切线的斜率K=-
=-1,
∴过点P的圆的切线方程为y-1=-(x-1),即为x+y-2=0.
故答案为x+y-2=0
| 2 |
| π |
| 4 |
| 2 |
| π |
| 4 |
| 2 |
| π |
| 4 |
∵圆ρ=
| 2 |
| x2+y2 |
| 2 |
∵点P(1,1)满足圆的方程,∴点P在圆上.
∵KOP=
| 1 |
| 1 |
∴过点P的圆的切线的斜率K=-
| 1 |
| KOP |
∴过点P的圆的切线方程为y-1=-(x-1),即为x+y-2=0.
故答案为x+y-2=0
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