题目内容
若等边△ABC的边长为2,平面内一点M满足
=
+
,则
•
=( )
| CM |
| 1 |
| 3 |
| CB |
| 1 |
| 2 |
| CA |
| MA |
| MB |
分析:先利用向量的运算法则将
,
分别用等边三角形的边对应的向量表示,利用向量的运算法则展开,据三角形的边长及边边的夹角已知,求出两个向量的数量积.
| MA |
| MB |
解答:解:由题意可得,
•
=|
||
|COS60°=2×2×
=2,
2=
2=4
∵
=
+
∴
=
-
=
-(
+
)=
-
=
-
=
-(
+
)=
-
∴
•
=(
-
)•(
-
)
=
•
-
2-
2
=
×2-
×4-
×4=-
故选C
| CA |
| CB |
| CA |
| CB |
| 1 |
| 2 |
| CA |
| CB |
∵
| CM |
| 1 |
| 3 |
| CB |
| 1 |
| 2 |
| CA |
∴
| MA |
| CA |
| CM |
| CA |
| 1 |
| 3 |
| CB |
| 1 |
| 2 |
| CA |
| 1 |
| 2 |
| CA |
| 1 |
| 3 |
| CB |
| MB |
| CB |
| CM |
| CB |
| 1 |
| 3 |
| CB |
| 1 |
| 2 |
| CA |
| 2 |
| 3 |
| CB |
| 1 |
| 2 |
| CA |
∴
| MA |
| MB |
| 1 |
| 2 |
| CA |
| 1 |
| 3 |
| CB |
| 2 |
| 3 |
| CB |
| 1 |
| 2 |
| CA |
=
| 1 |
| 2 |
| CA |
| CB |
| 1 |
| 4 |
| CA |
| 2 |
| 9 |
| CB |
=
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 9 |
| 8 |
| 9 |
故选C
点评:本试题考查了向量的数量积的基本运算.考查了基本知识的综合运用能力.
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