题目内容
(2006•海淀区二模)
(
-
)=
.
| lim |
| x→1 |
| 1 |
| x-1 |
| 2 |
| x2-1 |
| 1 |
| 2 |
| 1 |
| 2 |
分析:把极限符号后面的式子通分运算,约分后即可得到极限值.
解答:解:
(
-
)
=
=
=
=
.
故答案为
.
| lim |
| x→1 |
| 1 |
| x-1 |
| 2 |
| x2-1 |
=
| lim |
| x→1 |
| x+1-2 |
| x2-1 |
| lim |
| x→1 |
| x-1 |
| x2-1 |
| lim |
| x→1 |
| 1 |
| x+1 |
| 1 |
| 2 |
故答案为
| 1 |
| 2 |
点评:本题考查了极限及其运算,关键是消掉分母中的“0”项,是基础的计算题.
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