题目内容

化简[2sin500+sin100(1+
3
tan100)]
1+cos200
原式=[2sin50°+sin10°(1+
3
sin10°
cos10°
)]
1+cos200

=(2sin50°+sin10°•
cos10°+
3
sin10°
cos10°
1+cos200

=(2sin50°+2sin10°•
sin(10°+30°)
cos10°
1+cos200

=
2sin50°cos10°+2sin10°sin40°
cos10°
1+cos200

=2cos(40°-10°)•
2
cos10°
cos10°

=2cos30°×
2

=
6
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