Question

函数y=

2x2+1

的导数为______．

Answer 1

∵y=

2x2+1

=(2x2+1)

1

2

∴y′=

1

2

(2x2+1) -

1

2

•（2x²+1）′
=

1

2

•4x•(2x2+1)-

1

2

=

2x 1+2x2

1+2x2

故答案为

2x 2x2+1

2x2+1