题目内容
已知函数f(x)=sin2(
x)-
sin(
x)•cos(
x)
(Ⅰ)求f(x)的最大值及此时x的值;
(Ⅱ)求f(1)+f(2)+f(3)+…+f(2010)的值.
| π |
| 4 |
| 3 |
| π |
| 4 |
| π |
| 4 |
(Ⅰ)求f(x)的最大值及此时x的值;
(Ⅱ)求f(1)+f(2)+f(3)+…+f(2010)的值.
(I)f(x)=
-
cos
x-
sin
x=
-sin(
x+
)----(3分)
∴f(x)max=
,此时:
x+
=-
+2kπ,即x=4k-
.----(7分)
(II)周期=
=4,
f(1)+f(2)+f(3)+f(4)=
-sin(
+
)+
-sin(π+
)+
-sin(
+
)+
-sin(2π+
)=2
∵2010=4×502+2
∴原式=
+f(1)+f(2)=
+
-sin(
+
)+
-sin(π+
)=
----(14分)
| 1 |
| 2 |
| 1 |
| 2 |
| π |
| 2 |
| ||
| 2 |
| π |
| 2 |
| 1 |
| 2 |
| π |
| 2 |
| π |
| 6 |
∴f(x)max=
| 3 |
| 2 |
| π |
| 2 |
| π |
| 6 |
| π |
| 2 |
| 4 |
| 3 |
(II)周期=
| 2π | ||
|
f(1)+f(2)+f(3)+f(4)=
| 1 |
| 2 |
| π |
| 2 |
| π |
| 6 |
| 1 |
| 2 |
| π |
| 6 |
| 1 |
| 2 |
| 3π |
| 2 |
| π |
| 6 |
| 1 |
| 2 |
| π |
| 6 |
∵2010=4×502+2
∴原式=
| 2010 |
| 2 |
| 2010 |
| 2 |
| 1 |
| 2 |
| π |
| 2 |
| π |
| 6 |
| 1 |
| 2 |
| π |
| 6 |
2011-
| ||
| 2 |
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