题目内容

ξB(5,0.1),那么Pξ≤2)等于

A.0.0729               B.0.00856                     C.0.91854                    D.0.99144

解析:Pξ≤2)=Pξ=0)+Pξ=1)+Pξ=2)

=·(0.1)k·(0.9)5k

=(0.9)5+5·(0.1)·(0.9)4+·(0.1)2·(0.9)3

=0.59049+0.32805+0.0729

=0.99144.

答案:D

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