题目内容

【题目】(本小题满分12分)已知数列的首项

(1)求的通项公式;

(2)证明:对任意的.

【答案】解:(1)

∴ ∴

又 ∵

∴ 是以为首项,为公比的等比数列·········································4分

∴

∴ ································································6分

(2) 由 (1) 知···························································7分

∴ 原不等式成立··························································12分

【解析】略

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