题目内容
在锐角三角形ABC中,角A,B,C所对的边分别是a,b,c且tanB=
(1)求B;
(2)求sin(B+10°)[1-
tan(B-10°)]的值.
| ||
| a2+c2-b2 |
(1)求B;
(2)求sin(B+10°)[1-
| 3 |
(1)∵tanB=
,cosB=
,又tanB=
∴sinB=
B为锐角,∴B=60°
(2)∵B=60°,∴sin(B+10°)[1-
tan(B-10°)]
=sin70°(1-
tan50°)
=2sin70°
=-
=-1
| sinB |
| cosB |
| a2+c2-b2 |
| 2ac |
| ||
| a2+c2-b2 |
∴sinB=
| ||
| 2 |
(2)∵B=60°,∴sin(B+10°)[1-
| 3 |
=sin70°(1-
| 3 |
=2sin70°
| sin(30°-50°) |
| cos50° |
=-
| 2sin20°cos20° |
| sin40° |
=-1
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