题目内容
(3a
b
)(-6a
b
)÷(9
)的结果为
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 6 | ab5 |
-2a
-2a
.分析:利用根式与分数指数幂的互化及其化简运算,把(3a
b
)(-6a
b
)÷(9
)等价转化为3×(-6)÷9•a
+
-
•b
+
-
,由此能求出结果.
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 6 | ab5 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 2 |
| 1 |
| 3 |
| 5 |
| 6 |
解答:解:(3a
b
)(-6a
b
)÷(9
)
=3×(-6)÷9•a
+
-
•b
+
-
=-2a.
故答案为-2a.
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 6 | ab5 |
=3×(-6)÷9•a
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 2 |
| 1 |
| 3 |
| 5 |
| 6 |
=-2a.
故答案为-2a.
点评:本题考查根式与分数指数幂的互化及其化简运算,是基础题.解题时要认真审题,仔细解答.
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