题目内容
分析:由V=V ABC-A1B1C1=VP-ABC+V P-A1B1C1+V P-ACC 1 A1=
V+V P-ACC 1 A1,知V P-ACC 1 A1=
V,由V=3,能求出 V P-ACC 1 A1.
| 1 |
| 3 |
| 2 |
| 3 |
解答:解:V=V ABC-A1B1C1
=VP-ABC+V P-A1B1C1+V P-ACC 1 A1
=
×S底×PB+
×S底×PB1+V P-ACC 1 A1
=
×S底×(PB+PB1)+V P-ACC 1 A1
=
×S底×高+V P-ACC 1 A1
=
V+V P-ACC 1 A1,
∴V P-ACC 1 A1=
V,
∵V=3,∴V P-ACC 1 A1=2.
故选D.
=VP-ABC+V P-A1B1C1+V P-ACC 1 A1
=
| 1 |
| 3 |
| 1 |
| 3 |
=
| 1 |
| 3 |
=
| 1 |
| 3 |
=
| 1 |
| 3 |
∴V P-ACC 1 A1=
| 2 |
| 3 |
∵V=3,∴V P-ACC 1 A1=2.
故选D.
点评:本题考查棱柱和棱锥的体积的应用,是基础题.解题时要认真审题,仔细解答.
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