题目内容
若平面向量
,
,
两两所成的夹角是120°,且满足|
|=1,|
|=2,|
|=4,则|
+
+
|=______.
| a |
| b |
| c |
| a |
| b |
| c |
| a |
| b |
| c |
∵向量
,
,
两两所成的夹角是120°,
∴
•
=|
||
|cos120°=1×2×(-
)=-1
•
=|
|•|
cos120°=1×4×(-
)=-2
•
=|
•|
|cos120°=2×4×(-
)=-4
|
+
+
|=
+2
=
=
故答案为
| a |
| b |
| c |
∴
| a |
| b |
| a |
| b |
| 1 |
| 2 |
| a |
| c |
| a |
| c| |
| 1 |
| 2 |
| b |
| c |
| b| |
| c |
| 1 |
| 2 |
|
| a |
| b |
| c |
|
|
| b |
| c |
=
| 1+4+16-2-4-8 |
| 7 |
故答案为
| 7 |
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