题目内容
在①1⊆{0,1,2,3};②{1}∈{0,1,2,3};③{0,1,2,3}⊆{0,1,2,3};④∅?{0},上述四个关系中,错误的个数是( )A.1个
B.2个
C.3个
D.4个
【答案】分析:①1∈{0,1,2,3};②{1}⊆{0,1,2,3};③{0,1,2,3}⊆{0,1,2,3};④∅?{0}.
解答:解:①1∈{0,1,2,3},故①错误;
②{1}⊆{0,1,2,3},故②错误;
③{0,1,2,3}⊆{0,1,2,3},故③正确;
④∅?{0},故④正确.
故选B.
点评:本题考查集合的包含关系判断及应用,是基础题.解题时要认真审题,仔细解答.
解答:解:①1∈{0,1,2,3},故①错误;
②{1}⊆{0,1,2,3},故②错误;
③{0,1,2,3}⊆{0,1,2,3},故③正确;
④∅?{0},故④正确.
故选B.
点评:本题考查集合的包含关系判断及应用,是基础题.解题时要认真审题,仔细解答.
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