题目内容
平面内给定三个向量
=(3,2),
=(-1,2),
=(4,1).回答下列问题:
(1)若(
+k
)∥(2
-
),求实数k;
(2)设
=(x,y)满足(
-
)∥(
+
)且|
-
|=1,求
.
| a |
| b |
| c |
(1)若(
| a |
| c |
| b |
| a |
(2)设
| d |
| d |
| c |
| a |
| b |
| d |
| c |
| d |
解(1)∵(
+k
)∥(2
-
),
又
+k
=(3+4k,2+k),2
-
=(-5,2),
∴2×(3+4k)-(-5)×(2+k)=0,∴k=-
.
(2)∵
-
=(x-4,y-1),
+
=(2,4),
又(
-
)∥(
+
)且|
-
=1,
∴
,解得
或
.
∴
=(
,
),或
=(
,
).
| a |
| c |
| b |
| a |
又
| a |
| c |
| b |
| a |
∴2×(3+4k)-(-5)×(2+k)=0,∴k=-
| 16 |
| 13 |
(2)∵
| d |
| c |
| a |
| b |
又(
| d |
| c |
| a |
| b |
| d |
| c |
∴
|
|
|
∴
| d |
20+
| ||
| 5 |
5+2
| ||
| ,5 |
| d |
20-
| ||
| 5 |
5-2
| ||
| 5 |
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