题目内容
已知等比数列{an}中,各项都是正数,且2a2,
a1,3a3成等差数列,则
=( )
| 1 |
| 2 |
| a6+a7 | ||
|
A.
| B.2 | C.36 | D.12 |
设等比数列的公比为q,则
∴2a2,
a1,3a3成等差数列,
∴a1=2a2+3a3
∴a1=2a1q+3a1q2
∴1=2q+3q2
∴q=-1或q=
∵等比数列{an}中,各项都是正数,
∴q=
∴
=
=
=36
故选C.
∴2a2,
| 1 |
| 2 |
∴a1=2a2+3a3
∴a1=2a1q+3a1q2
∴1=2q+3q2
∴q=-1或q=
| 1 |
| 3 |
∵等比数列{an}中,各项都是正数,
∴q=
| 1 |
| 3 |
∴
| a6+a7 | ||
|
| a6+a7 |
| a9 |
| 1+q |
| q3 |
故选C.
练习册系列答案
相关题目