题目内容
已知向量
=(1,2),
=(2,-3).若向量
满足
+
)∥
,
⊥(
+
),则
=______.
| a |
| b |
| c |
| (c |
| a |
| b |
| c |
| a |
| b |
| c |
设
=(x,y),则
+
=(x+1,y+2),
又(
+
)∥
,
∴2(y+2)+3(x+1)=0. ①
又
⊥(
+
),
∴(x,y)•(3,-1)=3x-y=0. ②
解①②得x=-
,y=-
.
故应填:(-
,-
).
| c |
| c |
| a |
又(
| c |
| a |
| b |
∴2(y+2)+3(x+1)=0. ①
又
| c |
| a |
| b |
∴(x,y)•(3,-1)=3x-y=0. ②
解①②得x=-
| 7 |
| 9 |
| 7 |
| 3 |
故应填:(-
| 7 |
| 9 |
| 7 |
| 3 |
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