题目内容
1.正方体中,正四面体A1BC1D的体积是原正方体体积的( )| A. | $\frac{2}{3}$ | B. | $\frac{1}{2}$ | C. | $\frac{1}{3}$ | D. | $\frac{1}{4}$ |
分析 正四面体的体积等于正方体的体积减去4个全等的小三棱锥的体积.
解答 解:V${\;}_{{B}_{1}-{A}_{1}B{C}_{1}}$=V${\;}_{{D}_{1}-{A}_{1}{C}_{1}D}$=V${\;}_{A-{A}_{1}BD}$=V${\;}_{C-B{C}_{1}D}$
=$\frac{1}{3}{S}_{△BCD}•C{C}_{1}$=$\frac{1}{6}$S正方形ABCD•CC1=$\frac{1}{6}$V${\;}_{ABCD-{A}_{1}{B}_{1}{C}_{1}{D}_{1}}$,
∴V${\;}_{{A}_{1}-B{C}_{1}D}$=V${\;}_{ABCD-{A}_{1}{B}_{1}{C}_{1}{D}_{1}}$-4V${\;}_{C-B{C}_{1}D}$=$\frac{1}{3}$V${\;}_{ABCD-{A}_{1}{B}_{1}{C}_{1}{D}_{1}}$.
故选:C.
点评 本题考查了棱锥的体积计算,属于基础题.
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