题目内容
已知直线l1:x+my+6=0,l2:(m-2)x+3y+2m=0,求m的值,使得:
(1) l1⊥l2; (2) l1∥l2
解(1)当1·(m-2)+m·3=0,即m=时,l1⊥l2.
(2)当1×3=m(m-2)且1×2m≠6×(m-2)或m×2m≠3×6,即m=-1时,l1∥l2.
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题目内容
已知直线l1:x+my+6=0,l2:(m-2)x+3y+2m=0,求m的值,使得:
(1) l1⊥l2; (2) l1∥l2
解(1)当1·(m-2)+m·3=0,即m=时,l1⊥l2.
(2)当1×3=m(m-2)且1×2m≠6×(m-2)或m×2m≠3×6,即m=-1时,l1∥l2.