题目内容

(本小题满分12分)
在数列,中,a1=2,b1=4,且成等差数列,成等比数列()
(Ⅰ)求a2,a3,a4及b2,b3,b4,由此猜测,的通项公式,并证明你的结论;
(Ⅱ)证明:.

(Ⅰ),

(Ⅱ)略。

解析(Ⅰ)由条件得
由此可得
.······································ 2分
猜测.································································ 4分
用数学归纳法证明:
①当n=1时,由上可得结论成立.
②假设当n=k时,结论成立,即
,
那么当n=k+1时,
.
所以当n=k+1时,结论也成立.
由①②,可知对一切正整数都成立.······························· 7分
(Ⅱ).
n≥2时,由(Ⅰ)知.·································· 9分
故


综上,原不等式成立. ············································································ 12分

练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网