题目内容

如图,在正方体ABCD-A1B1C1D1中,EF分别是D1DD1B的中点.

求证:(1)平面

(2)平面.

 


 (1)证明: EF分别是D1DD1B的中点

 

面ABCD,DB面ABCD

EF// 面ABCD

(2)在正方体中,DD1面ABCD

 AC面ABCD

ACDD1

正方形ABCD, ACDB

又DD1 DB=D,

DD1 ,DB平面

平面

                                                                 

                                                               

 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 

                                                                 


                                                               

练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网