Question

已知集合A={x|x²-16＜0  }，集合B={x|x²-4x+3＞0 }，则A∩B=______．

Answer 1

A={x|x²-16＜0}={x|-4＜x＜4}，B={x|x²-4x+3＞0 }={x|x＜1或x＞3}
∴A∩B={x|-4＜x＜1或 3＜x＜4}
故答案为：{x|-4＜x＜1或 3＜x＜4}