题目内容
已知集合M={x|(x-1)2<4,x∈R},N={-1,0,1,2,3},则M∩N=( )
| A.{0,1,2} | B.{-1,0,1,2} | C.{-1,0,2,3} | D.{0,1,2,3} |
由(x-1)2<4,解得:-1<x<3,即M={x|-1<x<3},
∵N={-1,0,1,2,3},
∴M∩N={0,1,2}.
故选A
∵N={-1,0,1,2,3},
∴M∩N={0,1,2}.
故选A
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