题目内容
已知:a,b均为正数,| 1 |
| a |
| 4 |
| b |
分析:由题知a+b=
(a+b)(
+
) =
+
+
+2≥
+2
=
.由此可知答案.
| 1 |
| 2 |
| 1 |
| a |
| 4 |
| b |
| 1 |
| 2 |
| b |
| 2a |
| 2a |
| b |
| 5 |
| 2 |
|
| 9 |
| 2 |
解答:解:∵a,b均为正数,
+
=2,
∴a+b=
(a+b)(
+
) =
+
+
+2
≥
+2
=
.
∴c≤
.
答案:(-∞,
].
| 1 |
| a |
| 4 |
| b |
∴a+b=
| 1 |
| 2 |
| 1 |
| a |
| 4 |
| b |
| 1 |
| 2 |
| b |
| 2a |
| 2a |
| b |
≥
| 5 |
| 2 |
|
| 9 |
| 2 |
∴c≤
| 9 |
| 2 |
答案:(-∞,
| 9 |
| 2 |
点评:本题考查数列的性质和应用,解题时要认真审题,仔细解答.
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已知:a,b均为正数,
+
=2,则使a+b≥c恒成立的c的取值范围是( )
| 1 |
| a |
| 4 |
| b |
A、(-∞,
| ||
| B、(0,1] | ||
| C、(-∞,9] | ||
| D、(-∞,8] |