题目内容
已知函数f(x)=x2+ax+
-8,且f(-2)=10则f(2)的值为( )
| b |
| x |
| A.0 | B.-4 | C.-10 | D.-18 |
∵f(-2)=10
∴4-2a-
-8=10则2a+
=-14
f(2)=4+2a+
-8=4-14-8=-18
故选D.
∴4-2a-
| b |
| 2 |
| b |
| 2 |
f(2)=4+2a+
| b |
| 2 |
故选D.
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| b |
| x |
| A.0 | B.-4 | C.-10 | D.-18 |
| b |
| 2 |
| b |
| 2 |
| b |
| 2 |