题目内容
(文科)已知平面向量
=(2,-2),
=(3,4),
•
=
•
,则|
|的最小值是( )
| a |
| b |
| a |
| b |
| a |
| c |
| c |
| A.2 | B.
| C.
| D.
|
设
=(x,y),
∵
•
=
•
,
•
=2×3+(-2)×4=-2,
•
=2x-2y
∴2x-2y=-2
∴y-x=1
∵|
|=
=
=
=
≥
故当x=-
时,|
|最小值为
故选D
| c |
∵
| a |
| b |
| a |
| c |
| a |
| b |
| a |
| c |
∴2x-2y=-2
∴y-x=1
∵|
| c |
| x2+y2 |
| x2+(x+1)2 |
| 2x2+2x+1 |
=
2(x+
|
| ||
| 2 |
故当x=-
| 1 |
| 2 |
| c |
| ||
| 2 |
故选D
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