题目内容
求下列函数的导数:
(1)y=(x-2)(3x+4);
(2)y=
;
(3)y=x2+sin
cos
.
(1)y=(x-2)(3x+4);
(2)y=
| x3-1 |
| x2+1 |
(3)y=x2+sin
| x |
| 2 |
| x |
| 2 |
(1)y=(x-2)(3x+4)=3x2-2x-8,
y′=6x-2
(2)y′=
=
=
(3)y=x2+sin
cos
=x2+
sinx
所以y′=2x+
cosx
y′=6x-2
(2)y′=
| (x3-1)′(x2+1)-(x3-1)(x2+1)′ |
| (x2+1)2 |
=
| 3x2(x2+1)-2x(x3-1) |
| (x2+1)2 |
=
| x4+3x2+2x |
| (x2+1)2 |
(3)y=x2+sin
| x |
| 2 |
| x |
| 2 |
| 1 |
| 2 |
所以y′=2x+
| 1 |
| 2 |
练习册系列答案
相关题目