题目内容
| AB |
| AC |
| AM |
| 3 |
| 4 |
| a |
| 1 |
| 4 |
| b |
| 3 |
| 4 |
| a |
| 1 |
| 4 |
| b |
分析:根据题意,
=
,而
=
-
,将此代入
=
+
,可得用向量
、
表示
的式子.
| BM |
| 1 |
| 4 |
| BC |
| BC |
| b |
| a |
| AM |
| AB |
| BM |
| a |
| b |
| AM |
解答:解:∵
=
,
=
,∴
=
-
=
-
∵
=3
,∴
=
=
-
由此可得,
=
+
=
+(
-
)=
+
故答案为:
+
| AB |
| a |
| AC |
| b |
| BC |
| AC |
| AB |
| b |
| a |
∵
| CM |
| MB |
| BM |
| 1 |
| 4 |
| BC |
| 1 |
| 4 |
| b |
| 1 |
| 4 |
| a |
由此可得,
| AM |
| AB |
| BM |
| a |
| 1 |
| 4 |
| b |
| 1 |
| 4 |
| a |
| 3 |
| 4 |
| a |
| 1 |
| 4 |
| b |
故答案为:
| 3 |
| 4 |
| a |
| 1 |
| 4 |
| b |
点评:本题在△ABC中给出一边的四等分点,求一个向量用
、
线性表示的式子,着重考查了向量减法的意义和平面向量基本定理等知识,属于基础题.
| AB |
| AC |
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