题目内容
已知向量
=(1,cosx),
=(
,-sinx)
(1)当x∈[0,
]时,若
⊥
,求x的值;
(2)定义函数f(x)=
•(
-
),x∈R,求f(x)的最小正周期及最大值.
| a |
| b |
| 1 |
| 4 |
(1)当x∈[0,
| π |
| 4 |
| a |
| b |
(2)定义函数f(x)=
| a |
| a |
| b |
(1)若
⊥
,则
•
=
-sinxcosx=0,∴sin2x=
,∵x∈[0,
],
∴2x∈[0,
],∴2x=
,x=
.
(2)∵
-
=(
,cosx+sinx ),∴f(x)=
+cosx (cosx+sinx )=
+
=
+
sin(2x+
),
则 T=π,最大值为
+
,此时 x=kπ+
,k∈z.
| a |
| b |
| a |
| b |
| 1 |
| 4 |
| 1 |
| 2 |
| π |
| 4 |
∴2x∈[0,
| π |
| 2 |
| π |
| 6 |
| π |
| 12 |
(2)∵
| a |
| b |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
| 1+cos2x+sin2x |
| 2 |
=
| 5 |
| 4 |
| ||
| 2 |
| π |
| 4 |
则 T=π,最大值为
| 5 |
| 4 |
| ||
| 2 |
| π |
| 8 |
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