题目内容
已知sin(α+β)sin(β-α)=m,则cos2α-cos2β等于( )A.-m B.m C.-4m D.4m
解析:cos2α-cos2β=
(1+cos2α)
(1+cos2β)=![]()
=-sin(α+β)sin(α-β)=sin(α+β)sin(β-α)=m.
答案:B
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题目内容
已知sin(α+β)sin(β-α)=m,则cos2α-cos2β等于( )A.-m B.m C.-4m D.4m
解析:cos2α-cos2β=
(1+cos2α)
(1+cos2β)=![]()
=-sin(α+β)sin(α-β)=sin(α+β)sin(β-α)=m.
答案:B