题目内容

(本小题满分12分)已知数列的首项

(1)求的通项公式;

(2)证明:对任意的

 

【答案】

解:(1)      

    ∴

又 ∵      

是以为首项,为公比的等比数列················································· 4分

   

·························································································· 6分

(2) 由 (1) 知·········································································· 7分

∴ 原不等式成立····················································································· 12分

【解析】略

 

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