题目内容
曲线y=2x2在点P(1,2)处的切线方程是( )
| A.4x-y-2=0 | B.4x+y-2=O | C.4x+y+2=O | D.4x-y+2=0 |
∵曲线y=2x2过点P(1,2)
∴y′=4x,在点x=1斜率k=4×1=4,
∴y=2x2在点P(1,2)处的切线方程是:y-2=4(x-1),
∴4x-y-2=0,
故选A.
∴y′=4x,在点x=1斜率k=4×1=4,
∴y=2x2在点P(1,2)处的切线方程是:y-2=4(x-1),
∴4x-y-2=0,
故选A.
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