题目内容
已知θ是第二象限角,且sinθ=
,则tan(
-
)的值为______.
| 4 |
| 5 |
| θ |
| 2 |
| π |
| 4 |
∵θ是第二象限角,且sinθ=
,
∴cosθ=-
=-
,tanθ=-
,
∴tanθ=
=-
,即2tan2
-3tan
-2=0,
解得:tan
=-
(不合题意,舍去)或tan
=2,
则tan(
-
)=
=
=
.
故答案为:
| 4 |
| 5 |
∴cosθ=-
| 1-sin2θ |
| 3 |
| 5 |
| 4 |
| 3 |
∴tanθ=
2tan
| ||
1-tan2
|
| 4 |
| 3 |
| θ |
| 2 |
| θ |
| 2 |
解得:tan
| θ |
| 2 |
| 1 |
| 2 |
| θ |
| 2 |
则tan(
| θ |
| 2 |
| π |
| 4 |
tan
| ||
1+tan2
|
| 2-1 |
| 1+4 |
| 1 |
| 5 |
故答案为:
| 1 |
| 5 |
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