题目内容
若α是钝角,且sinα=
,则cos(α+
)的值为______.
| 1 |
| 3 |
| π |
| 6 |
因为sinα=
,且α是钝角,
所以cosα=-
=-
,
所以cos(α+
)=cosαcos
-sinαsin
=-
×
-
×
=
.
故答案为
.
| 1 |
| 3 |
所以cosα=-
1-
|
2
| ||
| 3 |
所以cos(α+
| π |
| 6 |
| π |
| 6 |
| π |
| 6 |
=-
2
| ||
| 3 |
| ||
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
=
-2
| ||
| 6 |
故答案为
-2
| ||
| 6 |
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