题目内容
计算:(1)a
(a、b是不为1的正数,c>0);
(2)lg5·lg8000+(lg2
)2-lg6+lg0.06;
(3)5
·(
)
;
(4)(log2125+log425+log85)·(log1258+log254+log52).
解:(1)∵logab·logbc=
=logac,∴a
=a
=c.
(2)原式=lg5(3+lg8)+(
lg2)2-lg6+lg6-2=(1-lg2)·3(1+lg2)+3lg22-2=3(1-lg22)+3lg22-2=1.
(3)设y=5
·(
)
,则lgy=lg5
+lg(
)
=lg30·lg5+lg0.5·lg![]()
=(1+lg3)lg5+lg2lg3=lg5+lg3(lg5+lg2)=lg5+lg3=lg15,∴y=15,即5
·(
)
=15.
(4)原式=(3log25+log25+
log25)(log52+log52+log52)=
log25·3log52=13.
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