题目内容

已知△OAB中,点D在线段OB上,且OD=2DB,延长BA到C,使BA=AC.设
OA
=
a
OB
=
b

(1)用
a
b
表示向量
OC
DC

(2)若向量
OC
OA
+k
DC
共线,求k的值.
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(1)∵A为BC的中点,∴
OA
=
1
2
(
OB
+
OC
)

可得
OC
=2
OA
-
OB
=2
a
-
b

DC
=
OC
-
OD
=
OC
-
2
3
OB
=2
a
-
5
3
b

(2)由(1),得
OA
+k
DC
=(2k+1)
a
-
5
3
k
b

OC
OA
+k
DC
共线,设
OC
=λ(
OA
+k
DC
)

2
a
-
b
=λ(2k+1)
a
+-
5
3
λk
b

根据平面向量基本定理,得
2=λ(2k+1)
-1=-
5
3
λk

解之得,k=
3
4
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