ÌâÄ¿ÄÚÈÝ

3£®ÀðÓãÊÇÉú»îÖг£¼ûµÄµ­Ë®Ó㣬¼È¿ÉÒÔʳÓÃÒ²ÓйÛÉͼÛÖµ£®ÀðÓãµÄÆ·ÖÖ¶àÑù£¬ÓÐÇà»Ò¡¢ºì¡¢À¶¡¢°×µÈ¶àÖÖÌåÉ«£¬ÓãÁÛµÄÁÛ±»³£¼ûµÄÊÇÈ«ÁÛÐÍ¡¢É¢ÁÛÐÍÁ½ÖÖ£®ÎªÌ½Ã÷ÀðÓãÌåÉ«¼°ÁÛ±»µÄÒÅ´«ÌØÐÔ£¬Ñо¿ÈËÔ±½øÐÐÁËÏÂÁÐʵÑ飮

£¨1£©ÓÉÔÓ½»Ò»ÊµÑé½á¹û¿ÉÖª£¬ÀðÓãµÄÌåÉ«ºÍÁÛ±»ÐÔ×´ÖеÄÇà»ÒÉ«¡¢È«ÁÛΪÏÔÐÔÐÔ×´£®F2ÖÐÇà»ÒÉ«£ººìÉ«=15£º1£¬È«ÁÛ£ºÉ¢ÁÛ=3£º1£¬ÓÉ´Ë¿ÉÖª£¬ÀðÓãµÄÌåÉ«ÊÇÓÉÁ½¶Ô»ùÒò¿ØÖƵģ¬ÁÛ±»ÐÔ×´ÊÇÓÉÒ»¶Ô»ùÒò¿ØÖƵģ®
£¨2£©Ñо¿ÈËÔ±ÔÚʵÑéÒ»µÄ»ù´¡ÉÏ£¬Ñ¡È¡F2ÖеÄÇà»ÒɫȫÁۺͺìɫȫÁÛÀðÓã¸÷1β½øÐÐÁËÔÓ½»ÊµÑé¶þ£®Óɽá¹û·ÖÎö¿ÉÖª£¬£¨ÈôÌåÉ«ÓÉÒ»¶ÔµÈλ»ùÒò¿ØÖÆÓÃA¡¢a±íʾ£¬ÓÉÁ½¶ÔµÈλ»ùÒò¿ØÖÆÓÃA¡¢aºÍB¡¢b±íʾ£»ÈôÁÛ±»ÓÉÒ»¶ÔµÈλ»ùÒò¿ØÖÆÓÃD¡¢d±íʾ£¬ÓÉÁ½¶ÔµÈλ»ùÒò¿ØÖÆÓÃD¡¢dºÍE¡¢e±íʾ£©ÊµÑé¶þµÄÇ×±¾Çà»ÒɫȫÁۺͺìɫȫÁÛÀðÓãµÄ»ùÒòÐÍ·Ö±ðÊÇAaBbDdºÍaabbDd£¬ÔÓ½»ºó´úÖУ¬Çà»ÒɫɢÁÛÀðÓã¸öÌåÕ¼$\frac{3}{16}$£®¿ØÖÆÌåÉ«ÓëÁÛ±»µÄ»ùÒò¹²Î»ÓÚÈý¶ÔȾɫÌåÉÏ£¬ËüÃǵÄÒÅ´«·ûºÏ£¨Ìî¡°·ûºÏ¡±»ò¡°²»·ûºÏ¡±£©×ÔÓÉ×éºÏ¶¨ÂÉ£®
£¨3£©Ñо¿±íÃ÷£¬ÀðÓãÌåÉ«ÖеĺìÉ«ºÍ°×É«¶¼ÊÇÓÉÓÚ»ùÒòÍ»±äÐγɵģ®ÎªÅжϺìÓë°×Ìåɫ֮¼äÊÇ·ñ´æÔÚÏÔÒþÐÔ¹ØÏµ£¬¿ÆÑÐÈËÔ±ÀûÓúìÀðºÍ°×Àð½øÐÐÌåÉ«¼äµÄÔÓ½»£¬ÔÙ´ÓF1¼ÒϵÖÐËæ»úѡȡ´ÆÐÛ¸÷2β½øÐн»Åä²úÉúF2£¬½á¹ûÈç±í£®
ÔÓ½»×éºÏF1F2
ºìÀð°×Àð
ºìÀ𣨡⣩¡Á°×À𣨡ᣩºìÀð829297
ºìÀ𣨡ᣩ¡Á°×À𣨡⣩ºìÀð825280
ʵÑé½á¹û±íÃ÷ºìÉ«ÐÔ×´¶Ô°×É«ÐÔ×´ÊÇÏÔÐÔ£®
×ۺϱ¾Ìâ¹ØÓÚÀðÓãµÄÌåÉ«µÄÔÓ½»ÊµÑé½á¹û¿ÉÒÔ¿´³ö£¬ÀðÓãÌåÉ«¼äµÄÏÔÒþÐÔ¹ØÏµ¾ßÓÐÏà¶ÔÐÔ£¬»áËæÔÓ½»Ç×±¾ÌåÉ«µÄ²»Í¬¶ø±íÏÖ³öÏÔÐÔ»òÒþÐÔ¹ØÏµ£®

·ÖÎö ¸ù¾ÝÌâÒâºÍͼʾ·ÖÎö¿ÉÖª£ºF2ÖÐÇà»ÒÉ«£ººìÉ«=15£º1ÊÇ9£º3£º3£º1µÄÌØÊâÇé¿ö£¬ËµÃ÷ÆäÒÅ´«ÊÇÓÉÁ½¶ÔµÈλ»ùÒò¿ØÖƵģ¬×ñÑ­»ùÒòµÄ×ÔÓÉ×éºÏ¶¨ÂÉ£®È«ÁÛ£ºÉ¢ÁÛ=3£º1£¬ËµÃ÷ÆäÒÅ´«ÊÇÓÉÒ»¶ÔµÈλ»ùÒò¿ØÖƵģ¬×ñÑ­»ùÒòµÄ·ÖÀ붨ÂÉ£®

½â´ð ½â£º£¨1£©¸ù¾ÝÒÅ´«Í¼ÖУ¬Ç×±¾ºìɫȫÁÛÓëÇà»ÒɫɢÁÛÔÓ½»£¬ºó´úÖ»ÓÐÇà»ÒɫȫÁÛ¿ÉÅжϣ¬ÀðÓãµÄÌåÉ«ºÍÁÛ±»ÐÔ×´ÖеÄÇà»ÒÉ«¡¢È«ÁÛΪÏÔÐÔÐÔ×´£®F2ÖÐÇà»ÒÉ«£ººìÉ«=15£º1£¬È«ÁÛ£ºÉ¢ÁÛ=3£º1£¬ÓÉ´Ë¿ÉÖª£¬ÀðÓãµÄÌåÉ«ÊÇÓÉÁ½¶Ô»ùÒò¿ØÖƵģ¬ÁÛ±»ÐÔ×´ÊÇÓÉÒ»¶Ô»ùÒò¿ØÖƵģ®
£¨2£©Ñ¡È¡F2ÖеÄÇà»ÒɫȫÁۺͺìɫȫÁÛÀðÓã¸÷1β½øÐÐÔÓ½»ÊµÑ飬¸ù¾Ý½á¹û·ÖÎö¿ÉÖª£¬Ç×±¾Çà»ÒɫȫÁۺͺìɫȫÁÛÀðÓãµÄ»ùÒòÐÍ·Ö±ðÊÇAaBbDdºÍaabbDd£¬ÔÓ½»ºó´úÖУ¬Çà»ÒɫɢÁÛÀðÓã¸öÌåÕ¼$\frac{3}{4}$¡Á$\frac{1}{4}$=$\frac{3}{16}$£®¿ØÖÆÌåÉ«ÓëÁÛ±»µÄ»ùÒò¹²Î»ÓÚÈý¶ÔȾɫÌåÉÏ£¬ËüÃǵÄÒÅ´«·ûºÏ»ùÒòµÄ×ÔÓÉ×éºÏ¶¨ÂÉ£®
£¨3£©ÔÓ½»×éºÏºìÀ𣨡⣩¡Á°×À𣨡ᣩºÍºìÀ𣨡ᣩ¡Á°×À𣨡⣩µÄºó´ú¶¼ÊǺìÀð£¬ËµÃ÷ºìÉ«ÐÔ×´¶Ô°×É«ÐÔ×´ÊÇÏÔÐÔ£®
×ۺϱ¾Ìâ¹ØÓÚÀðÓãµÄÌåÉ«µÄÔÓ½»ÊµÑé½á¹û¿ÉÒÔ¿´³ö£¬ÀðÓãÌåÉ«¼äµÄÏÔÒþÐÔ¹ØÏµ¾ßÓÐÏà¶ÔÐÔ£¬»áËæÔÓ½»Ç×±¾ÌåÉ«µÄ²»Í¬¶ø±íÏÖ³öÏÔÐÔ»òÒþÐÔ¹ØÏµ£®
¹Ê´ð°¸Îª£º
£¨1£©Çà»ÒÉ«¡¢È«ÁÛ    Á½     Ò»
£¨2£©AaBbDd     aabbDd      $\frac{3}{16}$    Èý    ·ûºÏ
£¨3£©ÏÔ   Ïà¶ÔÐÔ

µãÆÀ ±¾Ì⿼²é»ùÒò×ÔÓÉ×éºÏ¶¨ÂɵÄÏà¹ØÖªÊ¶£¬ÒâÔÚ¿¼²éѧÉúµÄʶͼÄÜÁ¦ºÍÅжÏÄÜÁ¦£¬ÔËÓÃËùѧ֪ʶ×ۺϷÖÎöÎÊÌâºÍ½â¾öÎÊÌâµÄÄÜÁ¦£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø