以铁为阳极、以铜为阴极,对足量的NaOH溶液进行电解。一段时间后得到了2molFe(OH)3沉淀,则得到这些沉淀,此间共消耗水的物质的量为( )
0 88828 88836 88842 88846 88852 88854 88858 88864 88866 88872 88878 88882 88884 88888 88894 88896 88902 88906 88908 88912 88914 88918 88920 88922 88923 88924 88926 88927 88928 88930 88932 88936 88938 88942 88944 88948 88954 88956 88962 88966 88968 88972 88978 88984 88986 88992 88996 88998 89004 89008 89014 89022 203614
A.2mol B.3mol C.4mol D.5mol