ÌâÄ¿ÄÚÈÝ

£¨13·Ö£© ij»ìºÏÎïAº¬ÓÐKAl(SO4)2¡¢Al2O3ºÍFe2O3£¬ÔÚÒ»¶¨Ìõ¼þÏ¿ÉʵÏÖÏÂͼËùʾµÄÎïÖÊÖ®¼äµÄ±ä»¯£º

¾Ý´Ë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©I¡¢II¡¢III¡¢IVËIJ½ÖжÔÓÚÈÜÒººÍ³ÁµíµÄ·ÖÀë²ÉÈ¡µÄ·½·¨ÊÇ            ¡£

£¨2£©¸ù¾ÝÉÏÊö¿òͼ·´Ó¦¹ØÏµ£¬Ð´³öÏÂÁÐB¡¢C¡¢D¡¢EËùº¬ÎïÖʵĻ¯Ñ§Ê½

¹ÌÌåB         £»³ÁµíC         £»³ÁµíD             £»ÈÜÒºE          ¡£

£¨3£©Ð´³ö¢Ù¡¢¢Ú¡¢¢Û¡¢¢ÜËĸö·´Ó¦·½³Ìʽ£¨¢Ú¡¢¢ÛдÀë×Ó·½³Ìʽ¢Ù¡¢¢Üд»¯Ñ§·½³Ìʽ£©

¢Ù                                                                        £»¢Ú                                                                        £»

¢Û                                                                        £»¢Ü                                                                        ¡£

 

¡¾´ð°¸¡¿

£¨13·Ö£©

£¨1£©¹ýÂË  £¨1·Ö£©

£¨2£©Al2O3£»Al2O3ºÍFe2O3£» Fe2O3£»K2SO4 ¡¢(NH4)2SO4  ºÍNH3•H2O£¨Ã¿¿Õ1·Ö£©

£¨3£©¢ÙAl2O3 + 2 NaOH +3H2O = 2 Na [Al(OH)4]£¨2·Ö£©

¢ÚAl3+£«3NH3•H2O£½Al(OH) 3¡ý£«3NH4+£¨2·Ö£©

¢Û[Al(OH)4]-£«H+£½Al(OH) 3¡ý£«H2O £¨2·Ö£©

¢Ü2Al(OH) 3 Al2O3£«3H2O £¨2·Ö£©

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ij»ìºÏÎïAº¬ÓÐKAl£¨SO4£©2¡¢Al2O3ºÍFe2O3£¬ÔÚÒ»¶¨Ìõ¼þÏ¿ÉʵÏÖÈçͼËùʾµÄÎïÖÊÖ®¼äµÄ±ä»¯£º

¾Ý´Ë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©I¡¢II¡¢III¡¢IVËIJ½ÖжÔÓÚÈÜÒººÍ³ÁµíµÄ·ÖÀë²ÉÈ¡µÄ·½·¨ÊÇ
¹ýÂË
¹ýÂË
£®
£¨2£©¸ù¾ÝÉÏÊö¿òͼ·´Ó¦¹ØÏµ£¬Ð´³öÏÂÁÐB¡¢D¡¢EËùº¬ÎïÖʵĻ¯Ñ§Ê½¹ÌÌåB
Al2O3
Al2O3
£»³ÁµíD
Fe2O3
Fe2O3
£»ÈÜÒºE
K2SO4ºÍ£¨NH4£©2SO4
K2SO4ºÍ£¨NH4£©2SO4
£®
£¨3£©Ð´³ö¢Ù¡¢¢ÜÁ½¸ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ
¢Ù
Al2O3+2NaOH=2NaAlO2+H2O
Al2O3+2NaOH=2NaAlO2+H2O
£»¢Ü
2Al£¨OH£©3
 ¸ßΠ
.
 
Al2O3+3H2O
2Al£¨OH£©3
 ¸ßΠ
.
 
Al2O3+3H2O
£®
£¨4£©Ð´³ö¢Ú¡¢¢ÛÁ½¸ö·´Ó¦µÄÀë×Ó·½³Ìʽ
¢Ú
Al3++3NH3?H2O=Al£¨OH£©3¡ý+3 NH4+
Al3++3NH3?H2O=Al£¨OH£©3¡ý+3 NH4+
£»¢Û
AlO2-+H++H2O=Al£¨OH£©3¡ý
AlO2-+H++H2O=Al£¨OH£©3¡ý
£®
£¨5£©Éè¼ÆÊµÑé¼ìÑéÈÜÒºFÖÐËùº¬ÈÜÖÊ£º
È¡FÈÜÒºÉÙÐíÓÚÁ½Ö§ÊÔ¹ÜÖУ¬Ò»Ö§ÖеμÓKSCNÈÜÒº£¬ÈôÏÔѪºìɫ֤Ã÷FÈÜÒºÖк¬ÓÐFe3+£»ÔÚÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëÏ¡ÏõËáËữȻºóÔÙ¼ÓÈëÏõËáÒøÈÜÒº£¬ÈôÓа×É«³ÁµíÉú³ÉÖ¤Ã÷FÈÜÒºÖк¬ÓÐCl-
È¡FÈÜÒºÉÙÐíÓÚÁ½Ö§ÊÔ¹ÜÖУ¬Ò»Ö§ÖеμÓKSCNÈÜÒº£¬ÈôÏÔѪºìɫ֤Ã÷FÈÜÒºÖк¬ÓÐFe3+£»ÔÚÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëÏ¡ÏõËáËữȻºóÔÙ¼ÓÈëÏõËáÒøÈÜÒº£¬ÈôÓа×É«³ÁµíÉú³ÉÖ¤Ã÷FÈÜÒºÖк¬ÓÐCl-
£®
£¨6£©·Ö±ðд³öAl2O3ºÍFe2O3ÔÚ¹¤ÒµÉϵÄÒ»ÖÖÖ÷ÒªÓÃ;£ºAl2O3
Ò±Á¶ÂÁ¡¢ÄÍ»ð²ÄÁÏ
Ò±Á¶ÂÁ¡¢ÄÍ»ð²ÄÁÏ
Fe2O3
Á¶ÌúÔ­ÁÏ¡¢ºìÉ«ÓÍÆá¡¢Í¿ÁÏ
Á¶ÌúÔ­ÁÏ¡¢ºìÉ«ÓÍÆá¡¢Í¿ÁÏ
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø