ÌâÄ¿ÄÚÈÝ

½ñÓÐÒ»»ìºÏÎïµÄË®ÈÜÒº£¬Ö»¿ÉÄܺ¬ÓÐÒÔÏÂÀë×ÓÖеÄÈô¸ÉÖÖ£ºK+¡¢¡¢Cl£­¡¢Mg2+¡¢Ba2+¡¢¡¢£¬ÏÖÈ¡Èý·Ý100 mLÈÜÒº½øÐÐÈçÏÂʵÑ飺

(1)µÚÒ»·Ý¼ÓÈëAgNO3ÈÜÒºÓгÁµí²úÉú

(2)µÚ¶þ·Ý¼Ó×ãÁ¿NaOHÈÜÒº¼ÓÈȺó£¬ÊÕ¼¯µ½ÆøÌå0.04 mol

(3)µÚÈý·Ý¼Ó×ãÁ¿BaCl2ÈÜÒººó£¬µÃ¸ÉÔï³Áµí6.27 g£¬¾­×ãÁ¿ÑÎËáÏ´µÓ¡¢¸ÉÔïºó£¬³ÁµíÖÊÁ¿Îª2.33 g£®¸ù¾ÝÉÏÊöʵÑ飬ÒÔÏÂÍÆ²âÕýÈ·µÄÊÇ

[¡¡¡¡]

A£®

K+Ò»¶¨´æÔÚ

B£®

100 mLÈÜÒºÖк¬0.01 mol¡¡CO

C£®

Cl£­Ò»¶¨´æÔÚ

D£®

Ba2+Ò»¶¨²»´æÔÚ£¬Mg2+¿ÉÄÜ´æÔÚ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø