ÌâÄ¿ÄÚÈÝ
A¡¢B¡¢C¡¢DÊÇËÄÖÖ³£¼ûµ¥ÖÊ£¬Æä¶ÔÓ¦ÔªËØµÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬¼×¡¢ÒÒ¡¢±ûΪ³£¼û»¯ºÏÎï¡£ËüÃÇÖ®¼äÓÐÈçÏÂת»¯¹ØÏµ¡£![]()
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)AµÄµç×ÓʽΪ_________£¬A¶ÔÓ¦µÄÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊǵÚ________ÖÜÆÚµÚ_______×å¡£
(2)BÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ__________________£¬DÓë¼×ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ__________________¡£
(3)Ò»¶¨Ìõ¼þÏ£¬2 mol BÓë3 mol DµÄÑõ»¯ÎïWÇ¡ºÃÍêÈ«·´Ó¦£¬ÔòWµÄÃû³ÆÎª_________¡£
(4)½øÐÐDÓëCµÄȼÉÕʵÑéʱ£¬Ó¦ÊÂÏÈÔÚ·´Ó¦ÈÝÆ÷ÖзÅÈëÉÙÁ¿_________£¬²úÎïÖÐÈÜÓÚË®ºóË®ÈÜÒº³Ê_________É«¡£
(1)H£ºH£»1ÖÜÆÚIA£»
(2)2A1+2NaOH+2H2O====2NaAlO2+3H2![]()
Fe+2Fe3+====3Fe2+
(3)Ñõ»¯ÑÇÌú
(4)ɰ×Ó(»òË®)£¬×Ø»Æ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
a¡¢b¡¢c¡¢dÊÇËÄÖÖ¶ÌÖÜÆÚÔªËØ£®a¡¢b¡¢dͬÖÜÆÚ£¬c¡¢dͬÖ÷×壮aµÄÔ×ӽṹʾÒâͼΪ
£¬bÓëcÐγɻ¯ºÏÎïµÄµç×ÓʽΪ
ÏÂÁбȽÏÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢Ô×Ó°ë¾¶£ºa£¾c£¾d£¾b | B¡¢×î¸ß¼Ûº¬ÑõËáµÄËáÐÔc£¾d£¾a | C¡¢Ô×ÓÐòÊý£ºa£¾d£¾b£¾c | D¡¢µ¥ÖʵÄÑõ»¯ÐÔa£¾b£¾d£¾c |