ÌâÄ¿ÄÚÈÝ
ÀûÓÃÈçͼËùʾװÖòⶨÖкÍÈȵÄʵÑé²½ÖèÈçÏ£º
![]()
¢ÙÓÃÁ¿Í²Á¿È¡50 mL 0.50 mol¡¤L£1ÑÎËáµ¹ÈëСÉÕ±ÖУ¬²â³öÑÎËáζȣ»
¢ÚÓÃÁíÒ»Á¿Í²Á¿È¡50 mL 0.55 mol¡¤L£1 NaOHÈÜÒº£¬²¢ÓÃÁíһζȼƲâ³öÆäζȣ»
¢Û½«NaOHÈÜÒºµ¹ÈëСÉÕ±ÖУ¬É跨ʹ֮»ìºÏ¾ùÔÈ£¬²âµÃ»ìºÏÒº×î¸ßζȣ¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÎªÊ²Ã´ËùÓÃNaOHÈÜÒºÒªÉÔ¹ýÁ¿£¿_________________________
£¨2£©µ¹ÈëNaOHÈÜÒºµÄÕýÈ·²Ù×÷ÊÇ______________(ÌîÐòºÅ)¡£
A£®Ñز£Á§°ô»ºÂýµ¹Èë B£®·ÖÈý´ÎÉÙÁ¿µ¹Èë C£®Ò»´ÎѸËÙµ¹Èë
£¨3£©Ê¹ÑÎËáÓëNaOHÈÜÒº»ìºÏ¾ùÔȵÄÕýÈ·²Ù×÷ÊÇ______________(ÌîÐòºÅ)¡£
A£®ÓÃζȼÆÐ¡ÐĽÁ°è B£®½Ò¿ªÓ²Ö½Æ¬Óò£Á§°ô½Á°è
C£®ÇáÇáµØÕñµ´ÉÕ± D£®ÓÃÌ×ÔÚζȼÆÉϵĻ·Ðβ£Á§½Á°è°ôÇáÇáµØ½Á¶¯
£¨4£©ÏÖ½«Ò»¶¨Á¿µÄÏ¡ÇâÑõ»¯ÄÆÈÜÒº¡¢Ï¡ÇâÑõ»¯¸ÆÈÜÒº¡¢Ï¡°±Ë®·Ö±ðºÍ1 L 1 mol¡¤L£1µÄÏ¡ÑÎËáÇ¡ºÃÍêÈ«·´Ó¦£¬Æä·´Ó¦ÈÈ·Ö±ðΪ¦¤H1¡¢¦¤H2¡¢¦¤H3£¬Ôò¦¤H1¡¢¦¤H2¡¢¦¤H3µÄ´óС¹ØÏµÎª______________¡£
£¨5£©______________(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)ÓÃBa(OH)2ÈÜÒººÍÁòËá´úÌæÇâÑõ»¯ÄÆÈÜÒººÍÑÎËᣬÀíÓÉÊÇ__________________¡£
![]()
ʵÑéÄ¿µÄ£ºÑо¿ÌúÓëŨÁòËáµÄ·´Ó¦
ʵÑéÒ©Æ·£ºÌú¶¤¡¢Å¨ÁòËá¡¢ËáÐÔKMnO4ÈÜÒº£¬Æ·ºìÈÜÒº¡¢CuO
ʵÑé²½Ö裺
ʵÑé²½Öè | ʵÑéÏÖÏó | ½áÂÛ |
½«Ìú¶¤£¨×ãÁ¿£©¼ÓÈëÉÕÆ¿ÖУ¬ÔÙÏòÆäÖеμӺ¬amolÁòËáµÄŨÁòËáÈÜÒº | δ¼ûÃ÷ÏÔÏÖÏó | ÔÒò£º |
µãȼA¡¢G´¦¾Æ¾«µÆ | Ƭ¿Ìºó£¬ÉÕÆ¿ÖÐÈÜÒºµÄÑÕÉ«·¢Éú±ä»¯£¬²¢ÓÐÆøÅݲúÉú¡£ | ÉÕÆ¿Öз¢ÉúµÄËùÓз´Ó¦ |
ÌîÍêÉÏÊöʵÑ鱨¸æ²¢»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Á¬½ÓºÃ×°Öúó£¬Ê¢·ÅҩƷǰ£¬Ê×ÏÈÒª½øÐÐ ²Ù×÷¡£
£¨2£©ÎªÁ˲ⶨ²úÉúµÄSO2µÄÁ¿£¬ÊµÑéºóÏòÉÕÆ¿ÖмÓ×ãÁ¿µÄÑÎËáÖÁÎÞÆøÅݲúÉú£¬ÔÙ¼Ó×ãÁ¿µÄBaCl2ÈÜÒºÖÁ³ÁµíÍêÈ«£¬ÎªÅжϳÁµíÍêÈ«£¬Ó¦¸Ã½øÐеIJÙ×÷ÊÇ£º £¬È»ºó½øÐйýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿¡£
£¨3£©Èô£¨2£©ÖÐËùµÃ³ÁµíµÄÖÊÁ¿Îªmg£¬Ôò·´Ó¦²úÉúµÄSO2ÔÚ±ê×¼×´¿öµÄÌå»ýΪ£¨Áгö¼ÆËãʽ¼´¿É£©£º L
Ò»¶¨Î¶ÈÏ£¬Ôڼס¢ÒÒ¡¢±û¡¢¶¡ËĸöºãÈÝÃܱÕÈÝÆ÷ÖÐͶÈëSO2(g)ºÍO2(g)£¬½øÐз´Ó¦£¬
2SO2+O2
2SO3£¬ÆäÆðʼÎïÖʵÄÁ¿¼°SO2µÄƽºâת»¯ÂÊÈçϱíËùʾ¡£ÏÂÁÐÅжÏÖÐÕýÈ·µÄÊÇ
¼× | ÒÒ | ±û | ¶¡ | ||
ÃܱÕÈÝÆ÷Ìå»ý/L | 2 | 2 | 2 | 1 | |
ÆðʼÎïÖʵÄÁ¿ | n(SO2)/mol | 0.40 | 0.80 | 0.80 | 0.40 |
n(O2)/mol | 0.24 | 0.24 | 0.48 | 0.24 | |
SO2µÄƽºâת»¯ÂÊ% | 80 |
|
|
| |
A£®¼×Öз´Ó¦µÄƽºâ³£ÊýСÓÚÒÒ
B£®¸ÃζÈÏ£¬¸Ã·´Ó¦µÄƽºâ³£ÊýKΪ400
C£®SO2µÄƽºâת»¯ÂÊ£º
1>
2 =
3
D£®ÈÝÆ÷ÖÐSO3µÄÎïÖʵÄÁ¿Å¨¶È£º±û=¶¡<¼×