ÌâÄ¿ÄÚÈÝ
2012Äê3ÔÂ22ÈÕÊǵڶþÊ®½ì¡°ÊÀ½çË®ÈÕ¡±£¬±£»¤Ë®×ÊÔ´£¬´ÓÎÒ×öÆð!
(1)C102ºÍC12(»¹Ô²úÎﶼΪClÒ»)ÊÇÉú»îÖг£ÓõÄÏû¶¾¼Á¡£µ±ÏûºÄµÈÎïÖʵÄÁ¿µÄÁ½ÖÖÎïÖÊʱ£¬C102µÄÏû¶¾Ð§ÂÊÊÇC12µÄ ±¶¡£
(2)×ÔÀ´Ë®³§³£ÓøßÌúËáÄÆ(Na2Fe04£¬Ç¿Ñõ»¯¼Á)¸ÄÉÆË®ÖÊ¡£¼òÊö¸ßÌúËáÄÆÓÃÓÚɱ¾úÏû¶¾Í¬Ê±ÓÖÆðµ½¾»Ë®×÷ÓõÄÔÀí£º £®
(3)ijÎÞÉ«·ÏË®ÖпÉÄܺ¬ÓÐFe3+¡¢A13+¡¢Mg2+¡¢Na+¡¢NO3-¡¢CO32Ò»¡¢SO42-Àë×ÓÖеļ¸ÖÖ£¬Îª·ÖÎöÆä³É·Ö£¬·Ö±ðÈ¡·ÏË®ÑùÆ·100 mL£¬½øÐÐÁËÈý×éʵÑ飬Æä²Ù×÷ºÍÓйØÏÖÏóÈçͼËùʾ£º
![]()
Çë¸ù¾ÝÉÏͼ»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙʵÑéÖÐÐèÅäÖÆ1£®0 mol£¯lµÄNaOHÈÜÒº80 ml£¬ËùÐèÒÇÆ÷³ýÁ˲£Á§°ô¡¢ÍÐÅÌÌìÆ½¡¢Á¿Í²¡¢Ò©³×¡¢ÉÕ±¡¢½ºÍ·µÎ¹Ü£¬»¹È±ÉÙµÄÒÇÆ÷Ϊ
¢ÚʵÑé¢ÛÖгÁµíÁ¿ÓÉA¡úB¹ý³ÌÖÐËù·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ ¡£
¢ÛÊÔÈ·¶¨NO3-ÊÇ·ñ´æÔÚ? (Ìî¡°´æÔÚ¡±¡°²»´æÔÚ¡±»ò¡°²»È·¶¨¡±)£¬Èô´æÔÚ£¬ÊÔ¼ÆËã
c(NO3-) (Èô²»´æÔÚ£¬´ËÎʲ»±Ø×÷´ð)¡£
ÏÂÁгýÔÓ·½°¸´íÎóµÄÊÇ(¡¡¡¡)
| Ñ¡Ïî | ±»Ìá´¿µÄÎïÖÊ | ÔÓÖÊ | ³ýÔÓÊÔ¼Á | ³ýÔÓ·½·¨ |
| A. | CO(g) | CO2(g) | NaOHÈÜÒº¡¢ ŨH2SO4 | Ï´Æø |
| B. | NH4Cl(aq) | Fe3£«(aq) | NaOHÈÜÒº | ¹ýÂË |
| C. | Cl2(g) | HCl(g) | ±¥ºÍʳÑÎË®¡¢ ŨH2SO4 | Ï´Æø |
| D. | Na2CO3(s) | NaHCO3(s) | ¡ª | ׯÉÕ |
ijͬѧÔÚʵÑéÊÒ´ÓÈçͼK352ÖÐ(¢ñ)±êÇ©µÄÊÔ¼ÁÆ¿ÖÐÈ¡ÉÙÐíÄÆ½øÐÐȼÉÕʵÑ飬ÈçͼK352ÖÐ(¢ò)¡£
![]()
¡¡¡¡¡¡¡¡¡¡¡¡¡¡(¢ñ)¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡¡(¢ò)
ͼK352
(1)×°ÖÃAµÄÃû³ÆÎª________£»ÊµÑéÖУ¬¹Û²ìµ½µÄµ»ÆÉ«µÄ¹ÌÌåÎïÖÊÊÇ________(д»¯Ñ§Ê½)£»¹Û²ìµ½µÄ»ÆÉ«»ðÑæÊÇ________ÔªËØµÄ·¢Éä¹âÆ×¡£
(2)ʵÑéºó·¢ÏÖ»¹ÓÐÉÙÐíºÚÉ«¹ÌÌåÉú³É¡£
´Ó·´Ó¦ÎPʵÑé²Ù×÷²Â²â£º¸ÃºÚÉ«ÎïÖÊ¿ÉÄÜΪ̼ÓëÁíÒ»ÖÖÑõ»¯Îï×é³ÉµÄ»ìºÏÎï¡£
Ôò¸ÃÑõ»¯Îï¿ÉÄÜÊÇ________»ò________(д»¯Ñ§Ê½)¡£
(3)¶ÔºÚÉ«¹ÌÌåÎïÖʵÄ×é³É×öÈçÏÂ̽¾¿£º
![]()
ͼK353
¢ÙʵÑé¢ñÖмÓÈëÑÎËáµÄÄ¿µÄÊÇ________________________________________________________________________
________________________________________________________________________¡£
¢Ú½öͨ¹ýʵÑé¢ò£¬ÓÃ×î¼òµÄ²½ÖèÄÜ¿ìËÙÈ·¶¨ºÚÉ«ÎïÖʵÄ×é³É£¬ÇëÍêÉÆ¸ÃÉè¼Æ¡£
[ÏÞÑ¡ÊÔ¼Á£ºÏ¡ÑÎËá¡¢KSCNÈÜÒº¡¢K3Fe(CN)6ÈÜÒº¡¢10%µÄH2O2ÈÜÒº]
| ʵÑé²Ù×÷ | Ô¤ÆÚµÄÏÖÏóÓë½áÂÛ | Ïà¹Ø»¯Ñ§·½³Ìʽ |
| È¡ÉÙÁ¿ÊµÑé¢ñÖеijÎÇåÈÜÒº£¬¼ÓÈë________ | ________________________________________________________________________ | ________________________________________________________________________ |