ÌâÄ¿ÄÚÈÝ


»¯Ñ§·´Ó¦Ô­ÀíÔÚ¿ÆÑк͹¤Å©ÒµÉú²úÖÐÓй㷺ӦÓá£

(1)ij»¯Ñ§ÐËȤС×é½øÐй¤ÒµºÏ³É°±µÄÄ£ÄâÑо¿£¬·´Ó¦µÄ·½³ÌʽΪN2(g)+3H2(g)2NH3(g) ¡£ÔÚlLÃܱÕÈÝÆ÷ÖмÓÈë0.1 mol N2ºÍ0.3mol H2£¬ÊµÑé¢Ù¡¢¢Ú¡¢¢ÛÖÐc(N2)ËæÊ±¼äµÄ±ä»¯ÈçÏÂͼËùʾ£º

ʵÑé¢Ú´Ó³õʼµ½Æ½ºâµÄ¹ý³ÌÖУ¬¸Ã·´Ó¦µÄƽ¾ù·´Ó¦ËÙÂÊv(NH3)=__________________£»ÓëʵÑé¢ÙÏà±È£¬ÊµÑé¢ÚºÍʵÑé¢ÛËù¸Ä±äµÄʵÑéÌõ¼þ·Ö±ðΪÏÂÁÐÑ¡ÏîÖеÄ__________¡¢__________(Ìî×Öĸ±àºÅ)¡£

a£®Ôö´óѹǿ  b£®¼õСѹǿ  C£®Éý¸ßζÈd£®½µµÍζȠ e£®Ê¹Óô߻¯¼Á

(2)ÒÑÖªNO2ÓëN2O4¿ÉÒÔÏ໥ת»¯£º¡£

¢ÙT¡æÊ±£¬½«0.40 mol NO2ÆøÌå³äÈëÈÝ»ýΪ2LµÄÃܱÕÈÝÆ÷ÖУ¬´ïµ½Æ½ºâºó£¬²âµÃÈÝÆ÷ÖÐc(N2O4)=0.05 mol¡¤L£¬Ôò¸Ã·´Ó¦µÄƽºâ³£ÊýK=_______________£»

¢ÚÒÑÖªN2O4ÔڽϸßζÈÏÂÄÑÒÔÎȶ¨´æÔÚ£¬Ò×ת»¯ÎªNO2£¬ÈôÉý¸ßζȣ¬ÉÏÊö·´Ó¦µÄƽºâ³£ÊýK½«_____________(Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±)¡£

¢ÛÏò¾øÈÈÃܱÕÈÝÆ÷ÖÐͨÈëÒ»¶¨Á¿µÄNO2£¬Ä³Ê±¼ä¶ÎÄÚÕý·´Ó¦ËÙÂÊËæÊ±Îʵı仯ÈçͼËùʾ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ__________(Ìî×Öĸ±àºÅ)¡£

A£®·´Ó¦ÔÚcµã´ïµ½Æ½ºâ״̬   

B£®·´Ó¦ÎïŨ¶È£ºaµãСÓÚbµã

C£®Ê±£¬NO2µÄת»¯ÂÊ£ºa¡«b¶ÎСÓÚ b¡«c¶Î

(3)25¡æÊ±£¬½«amol¡¤LµÄ°±Ë®Óëb mol¡¤LÒ»1ÑÎËáµÈÌå»ý»ìºÏ£¬·´Ó¦ºóÈÜҺǡºÃÏÔÖÐÐÔ£¬Ôòa___________b(Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±)£»ÓÃa¡¢b±íʾNH3H2OµÄµçÀëÆ½ºâ³£Êý=________________¡£


£¨1£©0.008mol¡¤L£­1¡¤min£­£¨2·Ö£©      e£¨1·Ö£© c£¨1·Ö£©

£¨2£©¢Ù5L¡¤mol£­1£¨2·Ö£© ¢Ú¼õС£¨2·Ö£©

¢ÛC£¨2·Ö£©

£¨3£©£¾£¨2·Ö£© £¨2·Ö£©


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø