Question

£¨12·Ö£©

£¨1£©ÊµÑéÊÒÓÃÂÈ»¯ï§¹ÌÌåÖÆÈ¡°±ÆøµÄ»¯Ñ§·½³ÌʽÊÇ          ¡£

£¨2£©½«4.48L£¨±ê×¼×´¿ö£©°±ÆøͨÈëË®Öеõ½0.05LÈÜÒº£¬ËùµÃÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ          ¡£

£¨3£©ÏÖÓÐ100mL AlCl₃ÓëMgSO₄µÄ»ìºÏÈÜÒº£¬·Ö³ÉÁ½µÈ·Ý¡£

¢ÙÏòÆäÖÐÒ»·ÝÖмÓÈë10mL 4mol/LµÄ°±Ë®£¬Ç¡ºÃÍêÈ«·´Ó¦£¬ÆäÖÐAlCl₃Ó백ˮ·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ           ¡£¼ÌÐø¼ÓÈël mol/L NaOHÈÜÒºÖÁ10mLʱ£¬³Áµí²»ÔÙ¼õÉÙ£¬³Áµí¼õÉÙµÄÀë×Ó·½³ÌʽÊÇ          £¬¼õÉٵijÁµíµÄÎïÖʵÄÁ¿ÊÇ          ¡£

¢ÚÏòÁíÒ»·ÝÖмÓÈëa mL 1mol/LBaCl₂ÈÜÒºÄÜʹSO₄^2£­³ÁµíÍêÈ«£¬a=           ¡£

 

Answer 1

£¨1£©Ca£¨OH£©₂£«2NH₄ClCaCl₂£«2H₂O£«2NH₃¡ü

£¨2£©4 mol/L

£¨3£©¢ÙA1³⁺£«3NH₃¡¤H₂O=Al£¨OH£©₃¡ý£«3NH₄⁺

Al£¨OH£©₃£«OH^£­=AlO₂^£­£«2H₂O

0.01 mol

¢Ú5

½âÎö:ÂÔ