ÌâÄ¿ÄÚÈÝ
ÔªËØÖÜÆÚÂɺÍÖÜÆÚ±í£¬½ÒʾÁËÔªËØÖ®¼äµÄÄÚÔÚÁªÏµ£¬·´Ó³ÁËÔªËØÐÔÖÊÓëËüµÄÔ×ӽṹµÄ¹ØÏµ£¬ÔÚÕÜѧ¡¢×ÔÈ»¿ÆÑ§¡¢Éú²úʵ¼ù¸÷·½Ãæ¶¼ÓÐÖØÒªÒâÒ塣ϱíÎªÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬Çë²ÎÕÕÔªËØ¢Ù¡«¢àÔÚ±íÖеÄλÖ㬻شðÏÂÁÐÎÊÌ⣺
£¨1£©Õâ8ÖÖÔªËØÖнðÊôÐÔ×îÇ¿µÄÔªËØÊÇ______£¨ÌîÔªËØ·ûºÅ»ò»¯Ñ§Ê½£¬ÏÂͬ£©£¬ÔªËØ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÖÐËáÐÔ×îÇ¿µÄËáÊÇ______£»
£¨2£©ÔªËØ¢àµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÓëÇâÑõ»¯ÄÆ·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_________£»
£¨3£©¢Û¡¢¢Ý¡¢¢ßÈýÖÖÔªËØ°´Ô×Ó°ë¾¶ÓÉ´óµ½Ð¡µÄ˳ÐòÅÅÁÐΪ___________£»
£¨4£©¢Ù¡¢¢Ü¡¢¢ÝÖеÄÄ³Ð©ÔªËØ¿ÉÐγɼȺ¬Àë×Ó¼üÓÖº¬¹²¼Û¼üµÄÀë×Ó»¯ºÏÎд³öÁ½ÖÖ»¯ºÏÎïµÄµç×Óʽ______________£¬______________¡£ÈôÓÃÇò¹÷Ä£Ðͱíʾ¢ÙºÍ¢ÜÐγɵϝºÏÎïµÄ·Ö×ӽṹ£¬Ó¦¸ÃÊÇ___________¡£
£¨5£©wÊǵÚËÄÖÜÆÚÓë¢ÛͬÖ÷×åµÄÔªËØ¡£¾Ý´ËÍÆ²âw²»¿ÉÄܾßÓеÄÐÔÖÊÊÇ
A£®×î¸ßÕý»¯ºÏ¼ÛΪ£«5¼Û B£®ÆøÌ¬Ç⻯Îï±ÈNH3Îȶ¨
C£®×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄËáÐÔ±ÈÏõËáÈõ D£®µ¥ÖÊÔÚ³£ÎÂÏ¿ÉÓëÇâÆø»¯ºÏ
£¨6£©ÓɱíÖÐÔªËØÐγɵij£¼ûÎïÖÊX¡¢Y¡¢Z¡¢M¡¢N¿É·¢ÉúÒÔÏ·´Ó¦£º
|
|
XÈÜÒºÓëYÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ_______£¬MÖÐÑôÀë×ӵļø¶¨·½·¨____________¡£
£¨1£©Na£¨1·Ö£© HClO4 £¨1·Ö£©
£¨2£©H++OH-=H2O £¨1·Ö£©
£¨3£©Na£¾Si£¾N£¨2·Ö£©
£¨4£©Na£«¡Ã
¡ÃH£ £¨1·Ö£©¡¢ Na£«¡Ã
¡Ã
¡Ã2£Na£«¡¡£¨1·Ö£© B £¨1·Ö£©
£¨5£© BD £¨2·Ö£©
£¨6£©Al3£«£«3NH3¡¤H2O===Al(OH)3¡ý£«3NH
£¨2·Ö£©
È¡ÉÙÁ¿MÑùÆ··ÅÈëÊԹܣ¬¼ÓÈëÇâÑõ»¯ÄÆÈÜÒº£¬¼ÓÈÈ£¬²úÉúÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶µÄÆøÌ壬֤Ã÷ÓÐ笠ùÀë×Ó£¨ÆäËüºÏÀí´ð°¸¸ø·Ö£©£¨2·Ö£©