ÌâÄ¿ÄÚÈÝ

Ïû³ýµªÑõ»¯ÎïºÍÁòÑõ»¯ÎïÓÐÖúÓÚÔ¤·ÀÎíö²ÌìÆøµÄÐγɡ£

£¨1£©Ä³ºãÈÝÃܱÕÈÝÆ÷ÖдæÔÚÈçÏ·´Ó¦£ºC(s)+2NO(g)N2(g)+CO2(g)¡÷H¡£Î¬³ÖζȲ»±ä£¬²âµÃ²»Í¬Ê±¿Ì¼¸ÖÖÆøÌåÎïÖʵÄŨ¶ÈÈçϱíËùʾ£º

¢Ù0~10minÄÚ£¬NOµÄƽ¾ù·´Ó¦ËÙÂÊv(NO)=___________£¬¸ÃζÈÏ·´Ó¦µÄƽºâ³£ÊýK=___________¡£

¢Ú±íÖÐ25minµÄÊý¾Ý±ä»¯Óë·´Ó¦½øÐе½22minʱ¸Ä±äÁË·´Ó¦ÌåϵÖеÄijһÌõ¼þÓйأ¬Ôòb=___________£¬¸Ä±äµÄÌõ¼þ¿ÉÄÜÊÇ___________¡£

A£®¼ÓÈëÒ»¶¨Á¿µÄ»îÐÔÌ¿

B£®Í¨ÈëÒ»¶¨Á¿µÄN2

C£®Êʵ±ËõСÈÝÆ÷µÄÌå»ý

¢ÛÈô15minʱÉý¸ßζȣ¬´ïµ½Æ½ºâʱÈÝÆ÷ÖÐNO¡¢N2¡¢CO2µÄŨ¶ÈÖ®±ÈΪ5:3:3£¬Ôò¡÷H___________0(Ìî¡°>¡±¡¢¡°=¡±»ò¡°<¡±)¡£

£¨2£©NH3´ß»¯»¹Ô­µªÑõ»¯Îï(²úÎïÊÇN2¡¢H2O)ÊÇĿǰ¹ã·º²ÉÓõÄÑÌÆøÍѵª¼¼Êõ

¢Ùµ±·ÏÆøÖÐNO2¡¢NOµÄÌå»ý·ÖÊýÏàµÈʱÍѵªÂÊ×î¸ß£¬Èô´ËÇé¿öÏÂÉú³É1molN2ʱ·´Ó¦·Å³öµÄÈÈÁ¿ÎªakJ£¬Ôò¶ÔÓ¦µÄÈÈ»¯Ñ§·½³ÌʽΪ___________¡£

¢ÚÓÒͼʹÓò»Í¬´ß»¯¼ÁʱµÄÍѵªÂÊ£¬ÔòÍѵªÊ±×î¼ÑµÄζȡ¢´ß»¯¼ÁÓ¦ÊÇ___________¡£

£¨3£©ÓÃʯ»Ò½¬×÷ÎüÊÕ¼ÁÒ²¿ÉÍÑÈ¥·ÏÆøÖеÄSO2£¬Èô´¦Àí½áÊøÊ±£¬²âµÃÎüÊÕÒºÖÐc(Ca2+)=0.70mol/L£¬Ôòc(SO32-)=___________(ÒÑÖªKsp(CaSO3)=1.4¡Á10-7)¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø