ÌâÄ¿ÄÚÈÝ
ÒÑ֪ij´¿¼îÊÔÑùÖк¬ÓÐNaClÔÓÖÊ£¬Îª²â¶¨ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊý£¬¿ÉÓÃÏÂͼÖеÄ×°ÖýøÐÐʵÑé¡££¨Ìáʾ£º¼îʯ»ÒÊÇÉúʯ»ÒÓëÇâÑõ»¯ÄƵĻìºÏÎ¿ÉÒÔÎüÊÕË®ºÍ¶þÑõ»¯Ì¼£©
![]()
Ö÷ҪʵÑé²½ÖèÈçÏ£º¢Ù °´Í¼×é×°ÒÇÆ÷£¬²¢¼ìÑé×°ÖÃµÄÆøÃÜÐÔ
¢Ú½«10.0 gÊÔÑù·ÅÈë×¶ÐÎÆ¿ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®Èܽ⣬µÃµ½ÊÔÑùÈÜÒº
¢Û³ÆÁ¿Ê¢Óмîʯ»ÒµÄUÐ͹ܵÄÖÊÁ¿£¬µÃµ½20.0 g
¢Ü´Ó·ÖҺ©¶·µÎÈë6 mol¡¤L£1µÄÁòËᣬֱµ½²»ÔÙ²úÉúÆøÌåʱΪֹ
¢Ý´Óµ¼¹ÜA´¦»º»ºÍ¨ÈëÒ»¶¨Á¿µÄ¿ÕÆø
¢ÞÔٴγÆÁ¿Ê¢Óмîʯ»ÒµÄUÐ͹ܵÄÖÊÁ¿£¬µÃµ½22.0 g
¢ßÖØ¸´²½Öè¢ÝºÍ¢ÞµÄ²Ù×÷£¬Ö±µ½UÐ͹ܵÄÖÊÁ¿»ù±¾²»±ä£¬Îª22.2 g
ÇëÌî¿ÕºÍ»Ø´ðÎÊÌ⣺
£¨1£©×°ÖÃÖиÉÔï¹ÜBµÄ×÷ÓÃ________________________¡£Èç¹ûûÓÐÁ¬½Ó¸Ã¸ÉÔï¹Ü£¬²âÊԵĽá¹û________________________£¨ÌîÆ«¸ß¡¢Æ«µÍ»ò²»±ä£©¡£
£¨2£©Èç¹û½«·ÖҺ©¶·ÖеÄÁòËá»»³ÉŨ¶ÈÏàͬµÄÑÎËᣬ²âÊԵĽá¹û________£¨ÌîÆ«¸ß¡¢Æ«µÍ»ò²»±ä£©¡£
£¨3£©²½Öè¢ÝµÄÄ¿µÄÊÇ________________________£¬Èç¹ûûÓнøÐв½Öè¢ÝµÄ²Ù×÷£¬²âÊԵĽá¹û________________£¨ÌîÆ«¸ß¡¢Æ«µÍ»ò²»±ä£©¡£
£¨4£©ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊýΪ________________________¡£
ʵÑéÊÒÓÃ50 mL 0.50 mol¡¤L£1ÑÎËá¡¢50 mL 0.55 mol¡¤L£1 NaOHÈÜÒººÍÈçͼËùʾװÖ㬽øÐвⶨÖкÍÈȵÄʵÑ飬µÃµ½±íÖеÄÊý¾Ý£º
ʵÑé´ÎÊý | ÆðʼζÈt1/¡æ | ÖÕֹζÈt2/¡æ | |
ÑÎËá | NaOHÈÜÒº | ||
1 | 20.2 | 20.3 | 23.7 |
2 2 | 20.3 | 20.5 | 23.8 |
3 | 21.5 | 21.6 | 24.9 |
![]()
Íê³ÉÏÂÁÐÎÊÌ⣺
£¨1£©²»ÄÜÓÃÍË¿½Á°è°ô´úÌæ»·Ðβ£Á§½Á°è°ôµÄÀíÓÉÊÇ_ ¡£
£¨2£©ÔÚ²Ù×÷ÕýÈ·µÄǰÌáÏ£¬Ìá¸ßÖкÍÈȲⶨ׼ȷÐԵĹؼüÊÇ_____________¡£´óÉÕ±Èç²»¸ÇÓ²Ö½°å£¬ÇóµÃµÄÖкÍÈÈÊýÖµ½« £¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족£©¡£½áºÏÈÕ³£Éú»îʵ¼Ê¸ÃʵÑéÔÚ ÖУ¨¼ÒÓòúÆ·£©Ð§¹û¸üºÃ¡£
£¨3£©¸ù¾ÝÉϱíÖÐËù²âÊý¾Ý½øÐмÆË㣬Ôò¸ÃʵÑé²âµÃµÄÖкÍÈȦ¤H£½___ [ÑÎËáºÍNaOHÈÜÒºµÄÃܶȰ´1 g¡¤cm£3¼ÆË㣬·´Ó¦ºó»ìºÏÈÜÒºµÄ±ÈÈÈÈÝ£¨c£©°´4.18 J¡¤£¨g¡¤¡æ£©£1¼ÆËã]¡£
£¨4£©ÈçÓÃ0.5 mol/LµÄÑÎËáÓëNaOH¹ÌÌå½øÐÐʵÑ飬ÔòʵÑéÖвâµÃµÄ¡°ÖкÍÈÈ¡±ÊýÖµ½«___ _£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°²»±ä¡±£©¡£Èç¸ÄÓÃ60 mL0.5 mol/LµÄÑÎËáÓë50 mL 0.55 mol¡¤L£1 µÄNaOH ÈÜÒº½øÐз´Ó¦£¬ÓëÉÏÊöʵÑéÏà±È£¬Ëù·Å³öµÄÈÈÁ¿ £¨Ìî¡°ÏàµÈ¡±»ò¡°²»ÏàµÈ¡±£©£¬ËùÇóÖкÍÈÈ £¨Ìî¡°ÏàµÈ¡±»ò¡°²»ÏàµÈ¡±£©¡£
£¨5£©ÈôijͬѧÀûÓÃÉÏÊö×°ÖÃ×öʵÑ飬ÓÐЩ²Ù×÷²»¹æ·¶£¬Ôì³É²âµÃÖкÍÈȵÄÊýֵƫµÍ£¬ÇëÄã·ÖÎö¿ÉÄܵÄÔÒòÊÇ ¡£
A.²âÁ¿ÑÎËáµÄζȺó£¬Î¶ȼÆÃ»ÓÐÓÃË®³åÏ´¸É¾»
B.°ÑÁ¿Í²ÖеÄÇâÑõ»¯ÄÆÈÜÒºµ¹ÈëСÉձʱ¶¯×÷³Ù»º
C.×ö±¾ÊµÑéµÄµ±ÌìÊÒνϸß
D.½«50mL0.55mol/LÇâÑõ»¯ÄÆÈÜҺȡ³ÉÁË50mL0.55mol/LµÄ°±Ë®
E.ÔÚÁ¿È¡ÑÎËáʱÑöÊÓ¼ÆÊý
F.´óÉÕ±µÄ¸Ç°åÖмäС¿×Ì«´ó
ijʵÑéС×éÉè¼ÆÓÃ50 mL 1.0 mol/LÑÎËá¸ú50 mL 1.1 mol/LÇâÑõ»¯ÄÆÈÜÒºÔÚÉÏͼװÖÃÖнøÐÐÖкͷ´Ó¦¡£ÔÚ´óÉÕ±µ×²¿µæÅÝÄËÜÁÏ£¨»òÖ½Ìõ£©£¬Ê¹·ÅÈëµÄСÉÕ±±¿ÚÓë´óÉÕ±±¿ÚÏàÆ½¡£È»ºóÔÙÔÚ´ó¡¢Ð¡ÉÕ±Ö®¼äÌîÂúËéÅÝÄËÜÁÏ£¨»òÖ½Ìõ£©£¬´óÉÕ±ÉÏÓÃÅÝÄËÜÁϰ壨»òÓ²Ö½°å£©×÷¸Ç°å£¬ÔÚ°åÖм俪Á½¸öС¿×£¬ÕýºÃʹζȼƺͻ·Ðβ£Á§½Á°è°ôͨ¹ý¡£Í¨¹ý²â¶¨·´Ó¦¹ý³ÌÖÐËù·Å³öµÄÈÈÁ¿¿É¼ÆËãÖкÍÈÈ¡£ÊԻشðÏÂÁÐÎÊÌ⣺
![]()
£¨1£©»·Ðβ£Á§½Á°è°ôµÄ×÷ÓÃÊÇ ¡£
£¨2£©±¾ÊµÑéÖÐÓÃÉÔ¹ýÁ¿µÄNaOHµÄÔÒò½Ì²ÄÖÐ˵ÊÇΪ±£Ö¤ÑÎËáÍêÈ«±»Öк͡£ÊÔÎÊ£ºÑÎËáÔÚ·´Ó¦ÖÐÈôÒòΪÓзÅÈÈÏÖÏ󣬶øÔì³ÉÉÙÁ¿ÑÎËáÔÚ·´Ó¦Öлӷ¢£¬Ôò²âµÃµÄÖкÍÈÈ____________£¨Ìî¡°Æ«´ó¡±¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©¡£
£¨3£©¸ÃʵÑéС×é×öÁËÈý´ÎʵÑ飬ÿ´ÎÈ¡ÈÜÒº¸÷50 mL£¬²¢¼Ç¼ÈçÏÂÔʼÊý¾Ý¡£
ʵÑéÐòºÅ | ÆðʼζÈt1/¡æ | ÖÕֹζÈt2/¡æ | βî(t2-t1)/¡æ | ||
ÑÎËá | NaOHÈÜÒº | ƽ¾ùÖµ | |||
1 | 25.1 | 24.9 | 25.0 | 31.6 | 6.6 |
2 | 25.1 | 25.1 | 25.1 | 30.6 | 5.5 |
3 | 25.1 | 25.1 | 25.1 | 31.9 | 6.8 |
ÒÑÖªÑÎËá¡¢NaOHÈÜÒºÃܶȽüËÆÎª1.00 g/cm3£¬Öкͺó»ìºÏÒºµÄ±ÈÈÈÈÝC=4.18¡Á10-3 kJ/(g¡¤¡æ)£¬Ôò¸Ã·´Ó¦µÄÖкÍÈÈΪ¦¤H=___________________¡£
£¨4£©ÈôÓõÈŨ¶ÈµÄ´×ËáÓëNaOHÈÜÒº·´Ó¦£¬Ôò²âµÃµÄÖкÍÈÈ»á_______________£¨Ìî¡°Æ«´ó¡±¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©£¬ÆäÔÒòÊÇ___________¡£
£¨5£©ÔÚÖкÍÈȲⶨʵÑéÖвâÁ¿ÆðʼζÈʱÐèÒªÁ½¸öζȼƣ¬Èç¹ûÖ»ÓÃÒ»¸öζȼƲâÁ¿£¬Ôò²âµÃµÄÖкÍÈÈÊýÖµ_______________£¨Ìî¡°Æ«´ó¡±¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©¡£